Answer
$n=-4$ is extraneous
Work Step by Step
$Given,$ $\sqrt (12-n)=n$
Checking for $n=-4$ :
$L.H.S=\sqrt (12-(-4))=\sqrt 16=4$
$R.H.S=-4$
$L.H.S$ does not equal $R.H.S$,hence $n=-4$ is extraneous
Checking for $n=3$:
$L.H.S=\sqrt (12-3)=\sqrt 9=3$
$R.H.S=3$
$L.H.S=R.H.S$,hence $n=3$ is not extraneous