Answer
Answers may vary
$\sqrt {x+1} = 2$
$\sqrt {x+6} = 3$
Work Step by Step
$\sqrt {x+1} = 2$
$(\sqrt {x+1})^2 = 2^2$
$x+1 = 4$
$x+1-1 = 4-1$
$x=3$
$\sqrt {x+6} = 3$
$(\sqrt {x+6})^2 = 3^2$
$x+6 = 9$
$x+6-6 = 9-6$
$x=3$
Algebra 1
by Hall, Prentice
Published by
Prentice Hall
ISBN 10:
0133500403
ISBN 13:
978-0-13350-040-0
Chapter 10 - Radical Expressions and Equations - 10-4 Solving Radical Equations - Practice and Problem-Solving Exercises - Page 624: 42
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