Answer
67 mph.
Work Step by Step
$(\frac{180000furlongs}{fortnight})(\frac{0.125mi}{furlong})(\frac{1 fortnight}{14days})(\frac{1day}{24h})=67 \frac{mi}{hour}$
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 28: 1.8
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