Answer
$2\times10^5$ drops.
Work Step by Step
Estimate the radius of a drop to be R=0.1 cm.
Calculate the drop volume $V = \frac{4 \pi}{3}(R)^3$.
The number of drops in 1.0 liter is $\frac{1000 cm^3}{V}=2\times10^5$ drops.
University Physics with Modern Physics (14th Edition)
by Young, Hugh D.; Freedman, Roger A.
Published by
Pearson
ISBN 10:
0321973615
ISBN 13:
978-0-32197-361-0
Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 28: 1.23
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