University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 28: 1.10

Answer

a) 88 ft/s b) $9.8 m/s^{2}$ c) $1000 kg/m^{3}$

Work Step by Step

100cm=1m and 1000g=1kg a) (60 mi/h)($\frac{1h}{3600s})(\frac{5280ft}{1 mi}$)= 88ft/s b) $(32 ft/s^{2})(\frac{30.48cm}{1ft})(\frac{1m}{100cm})= 9.8m/s^{2}$ c) $(1.0g/cm^{3})(\frac{100cm}{1m})^{3}(\frac{1kg}{1000g})= 1000kg/m^{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.