Answer
a) $4.10\times10^{5}$ µg/day
b) 0.900g
c) 2 tablets each day
d) 0.070 mg/day
Work Step by Step
1mg=$10^{-3}g$
1µg=$10^{-6}g$
1kg=$10^{3}g$
a) $(410mg/day)(\frac{10^{-3}g}{1mg})(\frac{1µg}{10^{-6}g})$= $4.10\times10^{5}$ µg/day
b) (12mg/kg)(75kg)=$(900mg)(\frac{10^{-3}g}{1mg})$=0.900g
c) mass of each tablet=m=(2.0mg)$(\frac{10^{-3}g}{1mg})$=$2.0\times10^{-3} g/tablet$
number of tablets required=$\frac{0.0030g/day}{2.0\times10^{-3} g/tablet}=1.5 tablet/day\approx2 tablet/day$
d) (0.000070 g/day)$(\frac{1mg}{10^{-3}g})$=0.070 mg/day