University Physics with Modern Physics (14th Edition)

Published by Pearson
ISBN 10: 0321973615
ISBN 13: 978-0-32197-361-0

Chapter 1 - Units, Physical Quantities, and Vectors - Problems - Exercises - Page 28: 1.14

Answer

a) $72 mm^{2}$ b) 0.50 c) 36 mm d) 6.0 mm e) 2.0

Work Step by Step

a) 12mm(5.98mm)=$71.76mm\approx72 mm^{2}$ (2 sig figs) b) $\frac{5.98mm}{12mm}= 0.49833333...\approx0.50$ (2 sig figs) c) 2(12mm)+2(5.98mm)= $35.96mm\approx36mm$ (to the nearest millimeter) d) 12mm-5.98mm= $6.02mm\approx6.0mm$ (2 sig figs) e) $\frac{12mm}{5.98mm}=2.00668896\approx2.0$ (2 sig figs)
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.