Answer
$Q=0.54\frac{m^3}{s}$
Work Step by Step
Knowing that: $W=Q\Delta P$
The maximum flow rate will be:
$Q=\frac{W}{\Delta P}=\frac{3.8\frac{kJ}{s}}{7kPa}=0.54\frac{m^3}{s}$
Thermodynamics: An Engineering Approach 8th Edition
by Cengel, Yunus; Boles, Michael
Published by
McGraw-Hill Education
ISBN 10:
0-07339-817-9
ISBN 13:
978-0-07339-817-4
Chapter 2 - Energy, Energy Transfer, and General Energy Analysis - Problems - Page 100: 2-50
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