Answer
$Money=55756.8\frac{dollars}{year}$
Work Step by Step
The energy that can be save at the classrooms at day is:
$E=200*12*110W*4\frac{h}{day}=1056\frac{kWh}{day}$
The energy that can be save at the faculty offices at day is:
$E=400*(\frac{12}{2})*110W*4\frac{h}{day}=1056\frac{kWh}{day}$
The total energy that can be save at day is:
$E=1056\frac{kWh}{day}+1056\frac{kWh}{day}=2112\frac{kWh}{day}$
And at year:
$E=2112\frac{kWh}{day}*\frac{240day}{1year}=506880\frac{kWh}{year}$
Finally the money that could be save is:
$Money=506880\frac{kWh}{year}*\frac{0.11dollars}{kWh}=55756.8\frac{dollars}{year}$
