Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 32 - Nuclear Physics and Nuclear Radiation - Problems and Conceptual Exercises - Page 1155: 91

Answer

$B).\ 1.2Ci$

Work Step by Step

We can find the activity of the sample as $R=\lambda N$ We plug in the known values to obtain: $R=(9.98\times 10^{-7})(4.5\times 10^{16})(\frac{1Ci}{3.7\times 10^{10}})$ $R=1.2\ Ci$
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