Answer
$A).\ 9.98\times 10^{-7}s^{-1}$
Work Step by Step
We can find the decay constant as
$\lambda=\frac{\ln2}{T_{\frac{1}{2}}}$
We plug in the known values to obtain:
$\lambda=\frac{\ln 2}{8.04d\times 86400s/d}=9.98\times 10^{-7}s^{-1}$
Physics Technology Update (4th Edition)
by Walker, James S.
Published by
Pearson
ISBN 10:
0-32190-308-0
ISBN 13:
978-0-32190-308-2
Chapter 32 - Nuclear Physics and Nuclear Radiation - Problems and Conceptual Exercises - Page 1155: 90
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