Answer
(a) $4.2\times 10^5rad$
(b) stays the same.
Work Step by Step
(a) We know that
$Q=mc_W\Delta T$
$\implies Q=(1.00Kg)(4186J/Kg.K)(1C^{\circ})=4186J$
Now we can find the required dosage as
$(\frac{4186J}{1.0Kg})(\frac{1rad}{0.01J/Kg})=4.2\times 10^5rad$
(b) We know that the dosage in rad is the amount of energy per unit mass. The dosage will not change.
