Physics Technology Update (4th Edition)

Published by Pearson
ISBN 10: 0-32190-308-0
ISBN 13: 978-0-32190-308-2

Chapter 32 - Nuclear Physics and Nuclear Radiation - Problems and Conceptual Exercises - Page 1155: 84

Answer

$33.5\times 10^6rad$

Work Step by Step

We know that $Dose \space in \space rad=(33.5\times 10^4J/Kg)(\frac{1rad}{0.001J/Kg})$ $Dose \space in \space rad=33.5\times 10^6rad$
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