Answer
5.06 m downward
Work Step by Step
Down is the negative direction:
$x= vt - \frac{1}{2}at^{2}$
$x= (-10.1)(1.20) - \frac{1}{2}(-9.8)(1.20)^{2}$
$x=-5.064$
$x\approx-5.06$
Hence, the displacement in the final 1.20s is 5.06 m downward
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 2 - Kinematics in One Dimension - Problems - Page 50: 55
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