Answer
1.5 $m/s^{2}$ down
Work Step by Step
Let down be the negative direction
$v=u+at$
$a=\frac{v-u}{t}$
$a=\frac{(-15)-(15)}{(20.0)}=-1.5\; m/s^{2}$
Hence, the acceleration is 1.5 $m/s^{2}$ down
Physics (10th Edition)
by Young, David; Stadler, Shane
Published by
Wiley
ISBN 10:
1118486897
ISBN 13:
978-1-11848-689-4
Chapter 2 - Kinematics in One Dimension - Problems - Page 50: 48
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