Answer
5.33 m
Work Step by Step
$v^{2}=u^{2}+2ax$
$(\frac{u}{2})^{2}=u^{2}+2(-9.8)(4.00)$
$\frac{3}{4}u^{2}=78.4$
$u\approx10.22415$ m/s
To find the maximum height reached:
$v^{2}=u^{2}+2ax$
$x=\frac{(0)^{2}-(10.22415)^{2}}{2(-9.8)}\approx5.33$ m
