Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 9 - Center of Mass and Linear Momentum - Problems - Page 256: 127

Answer

The fraction of the initial mass that must be burned and ejected is $~~0.0022$

Work Step by Step

We can use Equation (9-88) to find the final mass $M_f$ in terms of the initial mass $M_i$: $v_f-v_i = v_{rel}~ln(\frac{M_i}{M_f})$ $2.2~m/s = (1000~m/s)~ln(\frac{M_i}{M_f})$ $\frac{2.2~m/s}{1000~m/s} = ln(\frac{M_i}{M_f})$ $0.0022 = ln(\frac{M_i}{M_f})$ $e^{0.0022} = \frac{M_i}{M_f}$ $M_f = \frac{M_i}{e^{0.0022}}$ $M_f = 0.9978~M_i$ We can find the fraction of the initial mass that must be burned and ejected: $M_i-M_f = M_i-0.9978~M_i = 0.0022~M_i$ The fraction of the initial mass that must be burned and ejected is $~~0.0022$
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