Answer
The magnitude of the velocity is $~~4.01~m/s$
Work Step by Step
In part (a), we found that the velocity after the collision is: $~~(2.67~m/s)~\hat{i} + (-3.00~m/s)~\hat{j}$
We can find the magnitude of the velocity:
$v = \sqrt{(2.67~m/s)^2+(-3.00~m/s)^2}$
$v = 4.01~m/s$
The magnitude of the velocity is $~~4.01~m/s$.
