Answer
The direction of the velocity is an angle of $~~48^{\circ}~~$ below the positive x axis.
Work Step by Step
In part (a), we found that the velocity after the collision is: $~~(2.67~m/s)~\hat{i} + (-3.00~m/s)~\hat{j}$
We can find the direction of the velocity as an angle $\theta$ below the positive x axis:
$tan~\theta = \frac{3.00~m/s}{2.67~m/s}$
$\theta = tan^{-1}~(\frac{3.00~m/s}{2.67~m/s})$
$\theta = 48^{\circ}$
The direction of the velocity is an angle of $~~48^{\circ}~~$ below the positive x axis.
