Answer
$ P(1.11eV) = 7.13 \times 10^{-7}$
Work Step by Step
At E = 1.11 eV, the probability is
$ P(1.11eV) = \frac{1}{e^{1.11 eV - 0.744 eV/(8.62 \times 10^{-5} eV/K)(300K)} + 1}$
$ P(1.11eV) = 7.13 \times 10^{-7}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 41 - Conduction of Electricity in Solids - Problems - Page 1274: 36c
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