Answer
The angle of the velocity is below the horizontal.
Work Step by Step
Let "up" be the positive direction.
We can find the vertical component of the initial velocity:
$v_{0y} = (30~m/s)~sin~60^{\circ} = 25.98~m/s$
We can find the vertical component of velocity after $5.0~s$:
$v_y = v_{0y}+a_y~t$
$v_y = (25.98~m/s)+(-9.8~m/s^2)(5.0~s)$
$v_y = -23.0~m/s$
The negative sign shows that the vertical component of velocity is directed downward.
Therefore, the angle of the velocity is below the horizontal.
