Answer
$(-2.10\hat{i}+2.81\hat{j})\,m/s^{2}$
Work Step by Step
$\vec{a}_{avg}=\frac{\vec{v}_{f}-\vec{v}_{i}}{\Delta t}$
$=\frac{\textbf{0}-(6.30\hat{i}-8.42\hat{j})\,m/s}{3\,s}=\frac{(-6.30\hat{i}+8.42\hat{j})\,m/s}{3\,s}$
$=(-2.10\hat{i}+2.81\hat{j})\,m/s^{2}$
