Answer
$v = 16.3~m/s$
Work Step by Step
We can find the vertical component of the initial velocity:
$v_{0y} = (30~m/s)~sin~60^{\circ} = 25.98~m/s$
We can find the vertical component of velocity after $2.0~s$:
$v_y = v_{0y}+a_y~t$
$v_y = (25.98~m/s)+(-9.8~m/s^2)(2.0~s)$
$v_y = 6.38~m/s$
We can find the horizontal component of velocity:
$v_x = (30~m/s)~cos~60^{\circ} = 15~m/s$
We can find the magnitude of the velocity:
$v = \sqrt{(15~m/s)^2+(6.38~m/s)^2}$
$v = 16.3~m/s$
