Answer
$6.96^{\circ}$
Work Step by Step
We have the average velocity as;
$\bar{v_{avg}}=[(2.771)\hat{i}+(6.1428)\hat{j}+(0.8228\ km)\hat{k}] km/h$
The angle made by the average velocity with the horizontal is thus:
$\theta = tan^{-1}(\frac{0.8228}{\sqrt (6.1428^2+2.771^2)})$
$\theta=6.96^{\circ}$
