Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 90: 87a

Answer

With ground level chosen so $y_{0}=0,$ this equation gives the result $$ y_{\max }=\frac{1}{2} g t_{1}^{2}=\frac{1}{2}\left(9.8 \mathrm{m} / \mathrm{s}^{2}\right)(3.0 \mathrm{s})^{2}=44.1 \mathrm{m} $$

Work Step by Step

With ground level chosen so $y_{0}=0,$ this equation gives the result $$ y_{\max }=\frac{1}{2} g t_{1}^{2}=\frac{1}{2}\left(9.8 \mathrm{m} / \mathrm{s}^{2}\right)(3.0 \mathrm{s})^{2}=44.1 \mathrm{m} $$
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