Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 87: 58b

Answer

19 m/s

Work Step by Step

Given: Frequency $\nu=1200/min= \frac{1200}{60}s^{-1}=20.\,Hz$ Radius r= 0.15 m Equation: $v=2\pi r\nu$ Result: $v= 2\times\pi\times 0.15\,m\times20.\,s^{-1}=19\,m/s$
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