Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 88: 58c

Answer

$a = 2400~m/s^2$

Work Step by Step

In part (b), we found that $v = 19~m/s$ We can find the magnitude of the tip's acceleration: $a = \frac{v^2}{r}$ $a = \frac{(19~m/s)^2}{0.15~m}$ $a = 2400~m/s^2$
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