Answer
-58.3 m
Work Step by Step
$y= (v_{0}\sin \theta_{0})t-\frac{1}{2}gt^{2}$
$=(20.0\,m/s\times\sin 40.0^{\circ})\times5.00s-(\frac{1}{2}\times9.81\,m/s^{2} \times (5.00\,s)^{2})$
$=-58.3\,m$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 85: 26f
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