Answer
7.25 m
Work Step by Step
$y= (v_{0}\sin \theta_{0})t-\frac{1}{2}gt^{2}$
$=(20.0\,m/s\times\sin 40.0^{\circ})1.80s-(\frac{1}{2}\times9.81\,m/s^{2} \times (1.80\,s)^{2})$
$=7.25\,m$
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