Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 4 - Motion in Two and Three Dimensions - Problems - Page 85: 26b

Answer

8.21 m

Work Step by Step

$y= (v_{0}\sin \theta_{0})t-\frac{1}{2}gt^{2}$ $=(20.0\,m/s\times\sin 40.0^{\circ})1.10s-(\frac{1}{2}\times9.81\,m/s^{2} \times (1.10\,s)^{2})$ $=8.21\,m$
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