Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1147: 33b

Answer

$t = 1.60~years$

Work Step by Step

Let $u'$ be the velocity of the messenger relative to the reference frame S Then $u' = 0.950c$ Let $v$ be the velocity of the reference frame S relative to the armada Then $v = -0.800c$ We can find $u$: $u = \frac{u'+v}{1+u'~v/c^2}$ $u = \frac{0.950c-0.800c}{1+(0.950c)(-0.800c)/c^2}$ $u = 0.625c$ The speed of the messenger relative to the armada is $0.625~c$ We can find the time it takes the messenger to pass the armada: $t = \frac{1.00~ly}{0.625c}$ $t = 1.60~years$
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