Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 37 - Relativity - Problems - Page 1147: 23a

Answer

$\gamma=1.25$

Work Step by Step

We can find the lorentz factor as: $\gamma=\frac{1}{\sqrt{1-B^2}}$ We plug in the known values to obtain: $\gamma=\frac{1}{\sqrt{1-(0.600)^2}}=1.25$
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