Answer
$u=0.81c$
Work Step by Step
We know that
$u=\frac{u^{\prime}+v}{1+\frac{u^{\prime}v}{c^2}}$
We plug in the known values to obtain:
$u=\frac{0.40c+0.60c}{1+\frac{0.40c(0.60c)}{c^2}}$
$u=0.81c$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 37 - Relativity - Problems - Page 1147: 27
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