Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 36 - Diffraction - Problems - Page 1109: 9

Answer

$ 1.17mm$

Work Step by Step

First, we use a trig ratio to relate the angle, the distance to the minima, y, and the length to the screen, L. $\sin \theta =y/L$ Now we can use the above relationship and the give values in equation (36-3) to solve for the distance to the minima, y, Therefore; $\alpha \sin \theta = \Delta m \lambda $ where $m=1,2,3,....$ (minima) $\alpha (y/L) = \Delta m \lambda $ $y = \Delta m \lambda L / \alpha $ $y = (2-1) 589*10^{-9}m *3.00m / 0.001m $ $y = 1.17*10^{-3}m$ $y = 1.17mm$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.