Answer
$\alpha = 0$
Work Step by Step
In part (a) we found that $~~tan~\alpha = \alpha$
Note that when $\alpha = 0$, then $~~tan~\alpha = \alpha = 0$
Therefore, the smallest $\alpha$ is $~~\alpha = 0$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 36 - Diffraction - Problems - Page 1109: 17b
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