Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 36 - Diffraction - Problems - Page 1109: 17d

Answer

$\alpha = 4.493$

Work Step by Step

In part (a) we found that $~~tan~\alpha = \alpha$ We can use trial and error to find the second smallest value of $\alpha$: When $\alpha = 1:~~$ then $~~tan~1 = 1.557$ When $\alpha = 2:~~$ then $~~tan~2 = -2.185$ When $\alpha = 3:~~$ then $~~tan~3 = -0.1425$ When $\alpha = 4:~~$ then $~~tan~4 = 1.1578$ When $\alpha = 5:~~$ then $~~tan~5 = -3.38$ When $\alpha = 4.5:~~$ then $~~tan~4.5 = 4.637$ When $\alpha = 4.4:~~$ then $~~tan~4.4 = 3.096$ When $\alpha = 4.45:~~$ then $~~tan~4.45 = 3.72$ When $\alpha = 4.48:~~$ then $~~tan~4.48 = 4.225$ When $\alpha = 4.49:~~$ then $~~tan~4.49 = 4.42$ When $\alpha = 4.495:~~$ then $~~tan~4.495 = 4.527$ When $\alpha = 4.494:~~$ then $~~tan~4.494 = 4.506$ When $\alpha = 4.493:~~$ then $~~tan~4.493 = 4.485$ When $\alpha = 4.4935:~~$ then $~~tan~4.4935 = 4.495$ To three decimal places, the best estimate is $~~\alpha = 4.493$ The second smallest $\alpha$ is $~~\alpha = 4.493$
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