Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 36 - Diffraction - Problems - Page 1109: 17f

Answer

The third smallest $\alpha$ is $~~\alpha = 7.725$

Work Step by Step

In part (a) we found that $~~tan~\alpha = \alpha$ We can use trial and error to find the third smallest value of $\alpha$: When $\alpha = 5:~~$ then $~~tan~5 = -3.38$ When $\alpha = 6:~~$ then $~~tan~6 = -0.291$ When $\alpha = 7:~~$ then $~~tan~7 = 0.871$ When $\alpha = 8:~~$ then $~~tan~8 = -6.80$ When $\alpha = 7.5:~~$ then $~~tan~7.5 = 2.706$ When $\alpha = 7.8:~~$ then $~~tan~7.8 = 18.507$ When $\alpha = 7.7:~~$ then $~~tan~7.7 = 6.44$ When $\alpha = 7.75:~~$ then $~~tan~7.75 = 9.58$ When $\alpha = 7.72:~~$ then $~~tan~7.72 = 7.42$ When $\alpha = 7.73:~~$ then $~~tan~7.73 = 8.02$ When $\alpha = 7.725:~~$ then $~~tan~7.725 = 7.710$ When $\alpha = 7.726:~~$ then $~~tan~7.726 = 7.771$ When $\alpha = 7.7255:~~$ then $~~tan~7.7255 = 7.74$ To three decimal places, the best estimate is $~~\alpha = 7.725$ The third smallest $\alpha$ is $~~\alpha = 7.725$
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