Answer
$ \theta =0.18^{\circ}$
Work Step by Step
For this problem, we can use right triangle trigonometry with the given distance to the screen, d, and the distance to the point on the wall, y.
$\sin \theta = y/d$
$ \theta =\arcsin y/d$
$ \theta =\arcsin (0.011m/3.5m)$
$ \theta =0.18^{\circ}$
