Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 16 - Waves-I - Problems - Page 472: 9b

Answer

$k=16 m^{-1}$

Work Step by Step

As we know that $v=\frac{d}{t}$ putting $d=0.060 m$ and $t=0.0040 s$ $v=\frac{0.060}{0.0040}=15\frac{m}{s}$ The angular wave number$k=\frac{2\pi}{\lambda}=$ where $\lambda=0.40 m$ putting the values, we get $k=\frac{2(3.14)(0.40)}{0.40}=16 m^{-1}$
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