Answer
Amplitude $y_m=6.0 cm$
Work Step by Step
Comparing the given equation $y=6.0sin(0.020\pi{x}+4.0\pi{t})$ with $y_{(x,t)}=y_{m} sin(kx+\omega{t})$ we get $y_m=6.0$
and given that $x,y$ are expressed in centimeters so amplitude $y_m=6.0 cm$.
