Answer
$\lambda=1m$
Work Step by Step
Compare the given equation $y=6.0sin(0.020\pi{x}+4.0\pi{t})$ with $y_{(x,t)}=y_m sin(kx+\omega{t})$
$K=0.020{\pi}$
$k$ is known as wave number and we know that $k=\frac{2\pi}{\lambda}$
thus $\frac{2\pi}{\lambda}=0.020\pi$
or $\lambda=\frac{2}{0.020}=100cm=1m$
Thus wavelength $\lambda=1m$
