Answer
$v_{max}=75\frac{cm}{s}$
Work Step by Step
Maximum transverse speed can be determined from the following formula:
$v_{max}=2\pi{f}y_m$
putting the values, we get
$v_{max}=2(3.14)(2)(6cm)=75\frac{cm}{s}$
$v_{max}=75\frac{cm}{s}$
Fundamentals of Physics Extended (10th Edition)
by Halliday, David; Resnick, Robert; Walker, Jearl
Published by
Wiley
ISBN 10:
1-11823-072-8
ISBN 13:
978-1-11823-072-5
Chapter 16 - Waves-I - Problems - Page 472: 10f
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