Answer
$\alpha = 9.4~rad/s^2$
Work Step by Step
We can find the initial angular acceleration:
$\sum \tau = I~\alpha$
$\alpha = \frac{\sum \tau}{I}$
$\alpha = \frac{mg~d+F_a~h}{I}$
$\alpha = \frac{(70~kg)(9.8~m/s^2)(0.28~m)+(300~N)(1.4~m)}{65~kg~m^2}$
$\alpha = 9.4~rad/s^2$
