Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 290: 44a

Answer

$I = 2.0~kg~m^2$

Work Step by Step

We can find the rotational inertia: $I = 4\times (0.50~kg)(1.0~m)^2$ $I = 2.0~kg~m^2$
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