Answer
$0.06\ m/s^2$
Work Step by Step
Block 2 is released from rest.so its initial velocity $u=0\ m/s$
Distance through which block 2 falls $s =75\ cm$
Time taken to fall $t=5\ s$
Acceleration of the blocks can be calculating by using kinematics equation:
$s=ut+\frac{1}{2}at^2$
$0.75\ m=0+\frac{1}{2}a(5\ s)^2$
$a=\frac{2(0.75\ m)}{25\ s^2}$
$a=0.06\ m/s^2$
