Fundamentals of Physics Extended (10th Edition)

Published by Wiley
ISBN 10: 1-11823-072-8
ISBN 13: 978-1-11823-072-5

Chapter 10 - Rotation - Problems - Page 290: 51d

Answer

$1.2\ rad/s^2$

Work Step by Step

Radius of the axle $R=5\ cm =0.05\ m$ Acceleration $a =0.06\ m/s^2$ Therefore, angular acceleration $\alpha = \frac{a}{r}$ $\alpha= \frac{0.06\ m/s^2}{0.05\ m}$ $\alpha =1.2\ rad/s^2$
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