Answer
Please see the work below.
Work Step by Step
We know that
$V=V_{\circ}(1+B\Delta T)$
This can be rearranged as:
$B=\frac{(\frac{V}{V_{\circ}})-1}{\Delta T}$
We plug in the known values to obtain:
$B=\frac{\frac{1925}{2000}-1}{300-350}$
$B=75\times 10^{-5}K^{-1}$
Thus, it is ethyl alcohol.
