Answer
73 seconds
Work Step by Step
We find the total heat that is consumed:
$ Q = mL + mc\Delta T \\ Q=(.12)(334,000)+(.12)(4184)(37) \\ Q= 59 \times 10^3 J$
Thus, we find:
$ \Delta t = \frac{ 59 \times 10^3 J}{800W}=73s$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 17 - Exercises and Problems - Page 314: 40
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