Answer
Please see the work below.
Work Step by Step
We know that
$Q=mc\Delta T+(\frac{m}{2})L_v$
We plug in the known values to obtain:
$Q=(450000)(4184)(100-10)+(\frac{450000}{2})(2257000)$
$Q=6.773\times 10^{11}J$
Now we can find the time duration as
$t=\frac{Q}{P}$
We plug in the known values to obtain:
$t=\frac{6.773\times 10^{11}}{200\times 10^6}$
$t=3400s$
