Answer
4.88 degrees Celsius
Work Step by Step
We first find Q:
$Q = mc\Delta T = (.05)(4.184)(T) = .21 T$
We set this equal to the value of Q for the other process to find:
$ 1.025 = .21 T \\ T =4.88^{\circ}C$
Essential University Physics: Volume 1 (3rd Edition)
by Wolfson, Richard
Published by
Pearson
ISBN 10:
0321993721
ISBN 13:
978-0-32199-372-4
Chapter 17 - Exercises and Problems - Page 314: 53
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